This is resolved by using the Differential Operator ∂/∂t instead.
Dreaded Anomaly Send a noteboard - 06/12/2010 09:53:00 PM
Since e^x is independent of t.
This source of argument being that x might easily be time dependent, since e^x is clearly seen changing position during the joke and thus x=x(t)and d/dt[e^x(t)] does not necessarily equal zero
So this guy walks into a psychologist's office.
- 06/12/2010 02:39:31 PM
1149 Views
BAD JOKES!
- 06/12/2010 06:23:52 PM
753 Views
I cannot understand your first joke. I can't even get past the first line.
- 06/12/2010 07:36:48 PM
704 Views
It isn't particularly funny, you're not missing much. *NM*
- 06/12/2010 07:54:44 PM
284 Views
*NM*
Please. It was hi-larious.
- 06/12/2010 08:16:55 PM
699 Views
- 06/12/2010 09:13:19 PM
645 Views
Why is the "d/dt" part funny? I don't get the punchline but I understand the build up *NM*
- 06/12/2010 08:56:53 PM
315 Views
Because d/dt of e^x is 0
- 06/12/2010 09:01:35 PM
678 Views
I remember this starting a geek fight once
- 06/12/2010 09:23:47 PM
662 Views
This is resolved by using the Differential Operator ∂/∂t instead.
- 06/12/2010 09:53:00 PM
669 Views
- 06/12/2010 09:13:19 PM
645 Views