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That the weight of the city and/or clock (depending on whether whatever jiggerypokery you've got going on affect it's weight on the ground as well as on itself) is likely to crush the earth around it into a huge depression? Could affect how far away it's visible.
That the weight of the city and/or clock (depending on whether whatever jiggerypokery you've got going on affect it's weight on the ground as well as on itself) is likely to crush the earth around it into a huge depression? Could affect how far away it's visible.
Yep, it's foundation is not actually connected to the ground around it, it's buried deep in the earth, so I think I'm okay. For the size, your calculator agrees with what I've come up with, around 0.7 degrees. Since the full moon is 0.5 degrees, that's actually larger than it sounds. When I first saw 0.7 degrees as the answer I despaired, but after learning how that compares to the moon it all worked out.
As for the height to be seen above the horizon, that's some handy information. My world ... well, it sidesteps the curvature problem, I'll say.
Warder to starry_nite
Chapterfish — Nate's Writing Blog
http://chapterfish.wordpress.com
Chapterfish — Nate's Writing Blog
http://chapterfish.wordpress.com
Maths! And whether or not I am applying them correctly to a ridiculous fantasy situation.
- 01/08/2014 06:39:38 PM
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You didn't even spell it right.
- 01/08/2014 07:38:12 PM
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Would a thing 10 miles wide look bigger from 800 miles than a thing 2000 miles wide from 230,000?
- 02/08/2014 05:38:15 AM
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Re: Would a thing 10 miles wide look bigger from 800 miles than a thing 2000 miles ...
- 05/08/2014 05:14:08 AM
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I come bearing gifts of knowledge
- 02/08/2014 07:54:07 PM
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Have you considered
- 02/08/2014 08:00:44 PM
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Re: Have you considered
- 05/08/2014 05:06:25 AM
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Air quality would affect visibility anyway, and you have to calculate curvature of the Earth.
- 03/08/2014 03:18:42 AM
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Re: Air quality would affect visibility anyway, and you have to calculate curvature of the Earth.
- 05/08/2014 05:09:48 AM
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